Java – How to declare Hexadecimal literal ?

Published on March 2, 2016 by abundantcode

Filed under Java

Last modified March 2, 2016

Print this page

rate 1 star rate 2 star rate 3 star rate 4 star rate 5 star
Your rating: none, Average: 0 (0 votes)

This article have been viewed 5984 times

Problem statement

You need to declare an Hexadecimal literal in Java and display the result on a console window.

Solution

Hexadecimal numbers can contain numbers from 0-9 as well as characters A-F where A-F represents 10-15.

You can prefix the numbers with 0X to denote it as hexa decimal number as shown below.

public class Main {

    public static void main(String[] args) {
        int hexadecimalac1 = 0XA;
        int hexadecimalac2 = 0X15;
        System.out.println(hexadecimalac1);
        System.out.println(hexadecimalac2);
        
    }
}

The output of the above program will be

10

21

Leave a Comment


x

You might be Interested in these Posts

C# Program to swap two numbers without using temporary variable

Problem Write a program in Visual CSharp to swap two numbers using temporary variable and display t...

C# Program to swap two numbers

Problem Write a program in C# to swap two numbers using temporary variable and display the result i...

C# Program to print the sum of two numbers

Problem Write a program in C# to add two numbers and display the result in copnsole window. How to...