# C Program to find if the input is a Armstrong Number or Not

Published on December 21, 2016 by admin

Filed under C

rate 1 star rate 2 star rate 3 star rate 4 star rate 5 star # Problem

Write a program in C to find if a given number is Armstrong number or not.

# How to check if a number is a Armstrong number or not in C programming Language ?

A given number is a Armstrong number of order n if

abc… = an + bn + cn + …

For example , 371 is a Armstrong number because the result of the following leads to the number by itself.

3*3*3 + 7*7*7 + 1*1*1 = 371

```#include <stdio.h>
#include <math.h>
int main()
{
int inputNumber, temp, remainder;
int output = 0, index = 0 , i =0;
printf("Abundantcode.com coding samples \n");
printf("Enter the Number : ");
scanf("%d", &inputNumber);

temp = inputNumber;

while (temp != 0)
{
temp /= 10;
++index;
}

temp = inputNumber;

while (temp != 0)
{
remainder = temp%10;
output += pow(remainder,index);
temp /= 10;
}

if(output == inputNumber)
printf("%d is an Armstrong number.", inputNumber);
else
printf("%d is not an Armstrong number.", output);

return 0;
}```

### Output

Abundantcode.com coding samples

Enter the Number : 371
371 is an Armstrong number

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